LeetCode:922. Sort Array By Parity II

題目：
Given an array A of non-negative integers, half of the integers in A are odd, and half of the integers are even.
Sort the array so that whenever A[i] is odd, i is odd; and whenever A[i] is even, i is even.
You may return any answer array that satisfies this condition.

範例：

Input: [4,2,5,7]Output: [4,5,2,7]Explanation: [4,7,2,5], [2,5,4,7], [2,7,4,5] would also have been accepted.

解法：
這題還算簡單，簡單的排列，用雙數與單數的位置計數放值

func sortArrayByParityII(A []int) []int {    var odd, even = 1, 0	resultData := make([]int, len(A))	for _, data := range A {		if data%2 == 0 {			resultData[even] = data			even += 2		} else {			resultData[odd] = data			odd += 2		}	}    return resultData}